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Aleks [24]
2 years ago
5

Find the perimeter of a parallelogram and one semicircle

Mathematics
1 answer:
ch4aika [34]2 years ago
7 0

Answer:

  1. For semicircle examples, skip to section 1
  2. For parallelogram examples, skip to section 2

To find the perimeter of a parallelogram, use the formula, 2(a+b)

To find a semicircle perimeter, use the formula of (π × r) + (2 × r)

<em>note that without any specified values for the shapes, you cannot properly find a value.</em>

__________

1. \sf Semicircles

So let's say I have a bowl that is ironically shaped like a semicircle, and its radius is 6 units.

  • What we know is that the semicircle has a radius of 8 units, and what we must find is the perimeter.
  • So let's solve.

Use the formula from earlier.(Using 3.14 for pi)

(\pi *r)+(2*r)

=\pi * r(8) + 2 * r(8) = 41.12

__________

2. \sf Parallelograms

And let's say I have a new origami shape that contains a figure similar to a parallelogram. We want to find it's perimeter. What is the first step?

  • The first step is using the parallelogram perimeter formula as listed below and above.

2(a+b)

Where <em>a</em> is the side and <em>b</em> is the base.

  • And let's also say this figure has a base of 7 and a side of... let's say a side length of 9
  • Now that we have values, use the formula to solve.

2*(7+9) = 32

__________

\sf Questions

If you have any questions, please reach out via the comments. I hope this helps, and have a great day!

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konstantin123 [22]

Answer:

dryer cost = $450

Step-by-step explanation:

Given that:

washer + dryer = $841  ---- eq1

As washer costs $59 less than dryer So,

Dryer - $59 = washer

putting in eq1

Dryer + dryer - $59  = $841

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Dryer = $450

So the cost of washer will be:

washer = dryer - $59

Washer = $450 - $59

washer = $391

i hope it will help you!

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HELP!!!!!!!! Select an expression that id equivalent to 4squareroot of 2x^2 • 4squareroot of 2x^3
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Answer:

B

Step-by-step explanation:

\sqrt[4]{2x^2} *\sqrt[4]{2x^3} =(2x^2)^{1/4}*(2x^3)^{1/4}\\= 2^{1/4}*(x^2)^{1/4} *2^{1/4} * (x^3)^{1/4}\\

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