Help me pleaseeeeeeee

Rama09 [41]

Answer:

$F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

Step-by-step explanation:

$1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\
F\left(x+1\right)+f\left(x+2\right)-f\left(x+2\right)=2x+3f-f\left(x+2\right)

$

$2. \mathrm{Simplify}\\
F\left(x+1\right)=-xf+f+2x\\
$

$3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\ne \:-1\\
\frac{F\left(x+1\right)}{x+1}=-\frac{xf}{x+1}+\frac{f}{x+1}+\frac{2x}{x+1};\quad \:x\ne \:-1$

$4. \mathrm{Simplify}\\
F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

Final Answer: $F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1$

4 0

3 years ago

The diagram below shows the contents of a jar from which you select marbles at random.

Diano4ka-milaya [45]

TWO SCREENSHOT BELOW FOR THE ANSWER

3 0

3 years ago

Complete the solution of the equation. Find the<br> value of y when x equals -14.<br> -2x + 5y = 8

shepuryov [24]

Answer:

y = -4

Step-by-step explanation:

-2x + 5y = 8

Let x=-14

-2(-14) +5y = 8

28 +5y = 8

Subtract 28 from each side

28-28 +5y = 8-28

5y = -20

Divide by 5

5y/5 = -20/5

y = -4

4 0

3 years ago

Help me with this- 10 points

kotykmax [81]

Answer:

The model on the top right.

3 0

3 years ago

Read 2 more answers

Can someone help me with this

mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

${(x + 2)}^{2} + {(y + 3)}^{2} = 4$

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

$d = \sqrt{(x1 - x2) {}^{2} + {(y1 - y2)}^{2} } \\ r = \sqrt{ {( - 2 - 0)}^{2} + {( - 3 - ( - 3))}^{2} } \\ r = \sqrt{ {( - 2)}^{2} + {( - 3 + 3)}^{2} } \\ r = \sqrt{ {4}^{2} + 0 } \\ r = \sqrt{4} \\ r = 2$