Which statement about y=x^2-14x+45 is true

What is the value of 0.1561 rounded to the nearest tenth?

Ainat [17]

We have to round the value of 0.1561 to the nearest tenth.

The number after decimal is the number at tenth place. Consider the number to the right of the tenths place and use the number to determine if you will round up or stay the same. Notice that the number to the right of tenth place is more than or equal to 5 or less than 5. If that number is greater than or equal to 5, then the number will round up but if that number is less than 5, then the number will not round up. It will remain same.

Let us consider the given number 0.1561

The number at tenths place is 1

The number after the tenths place is 5 (which is either greater than or equal to 5)

So, the number will round up to 0.2

8 0

3 years ago

Read 2 more answers

What is 26/57= 849/5x

Leto [7]

$\frac{26}{57}=\frac{849}{5}x \\ \\ x=\left(\frac{26}{57} \right) \left(\frac{5}{849} \right) \\ \\ x=\boxed{130/48393}$

4 0

1 year ago

A piece of fabric is 1/3 yard by 3 5/8 yards. Irma solves 1/3⋅3 5/8 to find the area of the fabric in square yards. Enter number

Harlamova29_29 [7]

For this case we have:

The area of the piece of fabric is given by $A = a * b$

Where

$a = \frac{1}{3}yards$

$b = 3 \frac{5}{8}yards$

Substituting in the formula of the area we have:

$A = \frac{1}{3}* 3 \frac{5}{8}\\$

$A = \frac{1}{3}* (3 + \frac{5}{8})\\$

$A = 1 + \frac{5}{24}$

$A = 1\frac{5}{24}yards ^ 2\\$

Thus, the area of the piece of fabric is given by: $A = 1\frac{5}{24}yards ^ 2\\$

Answer:

$A = 1\frac{5}{24}yards ^ 2\\$

4 0

4 years ago

Give two reasons as to why Awadh was important..<br><br><br> I will mark brainliest

OLga [1]

Answer:

Awadh which was popularly known as the granary of India, was important (strategically) for the control of the Doab, a fertile plain between the Ganges and the Yamuna rivers. It was a wealthy kingdom, able to maintain its independence against threats from the Marathas, the British and the Afghans.

4 0

4 years ago

Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1

nikklg [1K]

Given

$\Sigma_{n=1}^\infty15(-4)^n$

The first 10 partial sums are as follows:

$S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\ \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\ \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\ \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\ \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}$

$S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}$

The rest of the partial sums can be obtained in similar way.

7 0

3 years ago