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nataly862011 [7]
2 years ago
5

Can someone please help me! I am going crazy with this simple question:(

Biology
1 answer:
bija089 [108]2 years ago
3 0

Answer: Option C- 12 g                                                                                                                                  .

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A woman and a man are both heterozygous for a recessive allele for a rare genetic disease. If they have one child, what is the p
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Answer:

  • If they have one child, the probability that he or she will be affected is 1/4.
  • If they have two children, the probability that at least one of them will be affected is 7/16.

Explanation:

A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.

Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.

Every time they have children new gametes were generated <u>independently</u>.

The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).

The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.

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A student wants to use a spinning basketball to model the day and not cycle on Earth
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Answer: Shine a bright light on one side of the ball.

Explanation: The light replicates the Sun shining light on one side of the Earth.

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On inspection of a client's legs, the nurse has found varicose veins. which test should the nurse next perform to determine the
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