The most common type of joint which are freely movable are called
1 answer:
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Answer:
q = 0.42
Explanation:
This question is an example of Hardy-Weinberg question and there are two equations necessary to carry out this question;
p + q = 1
p² + 2pq + q² = 1
where;
p = the frequency of the dominant allele
q = the frequency of the recessive allele
p² = the frequency of individuals with homozygous dominant genotype
2pq = the frequency of individuals with heterozygous genotype
q² = frequency of individuals with the homozygous recessive genotype
Since the total population = 425
q² =
=
q² = 0.1765
To find q; we need to square root both side to eliminate the square from q².
∴
q = 0.4201
q = 0.42 (to two decimal places)