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chubhunter [2.5K]
2 years ago
10

If 0.380 mol of barium nitrate is allowed to react with an excess of phosphoric acid, how many moles of barium phosphate could b

e formed?
Ba (NO3)2+ H3PO4 → Ba3(PO4)2+ HNO3
Chemistry
1 answer:
Vladimir [108]2 years ago
7 0

If 0.380 mol of barium nitrate is allowed to react with an excess of phosphoric acid, 0.127 moles of barium phosphate could be formed.

<h3>How to calculate number of moles?</h3>

The number of moles of a compound can be calculated stoichiometrically as follows:

Based on this question, the following chemical equation is given:

Ba (NO3)2+ H3PO4 → Ba3(PO4)2+ HNO3

The balanced equation is as follows:

3Ba(NO3)2 + 2H3PO4 → Ba3(PO4)2 + 6HNO3

3 moles of barium nitrate produces 1 mole of barium phosphate

Therefore, 0.380 moles of barium nitrate will produce 0.380/3 = 0.127moles of barium phosphate.

Learn more about stoichiometry at: brainly.com/question/9743981

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