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bagirrra123 [75]
2 years ago
10

I need help with this question please

Mathematics
1 answer:
Verizon [17]2 years ago
5 0

Answer:

85 cm

Step-by-step explanation:

the strut forms a right triangle with the end of the pole.

let the ends of the strut be x from the top of the pole . then

using Pythagoras' identity with 2 legs x and hypotenuse 1.2

x² + x² = 1.2²

2x² = 1.44 ( divide both sides by 2 )

x² = 0.72 ( take square root of both sides )

x = \sqrt{0.72} ≈ 0.85 m ( to 2 dec. places )

the ends are 0.85 m = 85 cm from the top of the pole

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The degree of the polynomial function f(x) is 4. The roots of the equation f(x)=0 are −2, −1, 1 and 3.
Sergio [31]

Answer:

f(x) = x^4 - x^3 - 7x^2 + x + 6

Step-by-step explanation:

Please, always share the instructions with every question you post.  I am assuming that you are to write out the factors corresponding to the given roots, thus constructing a 4th degree polynomial, and then performng the multiplication necesssary to produce that polynomial with terms in descending order by power of x.  Note that there must be 5 such terms.

f(x) = (x + 2)(x + 1)(x - 1)(x - 3)

Multiplying this out, we get:  

f(x) = (x + 2)(x^2 - 1)(x - 3), or

f(x) =      (x^3 - x + 2x^2 - 2)(x - 3), or:

f(x) = (x^3 + 2x^2 - x - 2)(x - 3), or:

f(x) = x^4 + 2x^3 - x^2 - 2x - 3x^3 - 6x^2 + 3x + 6

Combining like terms, we get:

f(x) = x^4 - x^3 - 7x^2 + x + 6

Note that because this is a 4th degree polynomial, the end behavior resembles that of the graph of y = x^4.  As x increases, y initially decreases in Quadrant II, passes through the y-intercept (0, 6), and then increases without bound in Quadrant I.

5 0
4 years ago
A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just b
DedPeter [7]

Complete question:

A student throws a heavy ball downward off the top of a building with a speed of 18m/s. The ball reaches a speed of 41m/s just before striking the ground. Neglect drag, find the height of the building.

Answer:

The height of the building is 69.235 m

Step-by-step explanation:

Given;

initial velocity of the ball, u = 18 m/s

final velocity of the ball, v = 41 m/s

The height of the building is equal to distance traveled by the ball downward.

Apply the following kinematic equation;

v² = u² + 2gh

where;

g is acceleration due to gravity

h is height of the building

41² = 18² + 2(9.8)h

1681 = 324 + 19.6h

19.6h = 1681 - 324

19.6h = 1357

h = 1357 / 19.6

h = 69.235 m

Therefore, the height of the building is 69.235 m

4 0
3 years ago
Adjacent Angles:<br><br>Answer:​
lakkis [162]

Hey there!

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Hope it helps and have a great day!!!!

5 0
3 years ago
At 12 noon, Leslie recorded the temperature as 56 degrees. The temperature had increased by 8 degrees from 10 am. The temperatur
BaLLatris [955]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Whats the perimeter and area of this shape?
stich3 [128]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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