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Anika [276]
4 years ago
13

Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake

on? Tell me the number of the reason he got wrong and which property he should have used instead (use your blue foldable, if needed).
Statements

1. 2(3x + 4) = 56
Reasons

1. Given

2. 6x + 8 = 56
2. Multiplication Property of Equality
3. 6x + 8 - 8 = 56 - 8
3. Subtraction Property of Equality
4. 6x = 48 4. Simplify

5. 6x6=486 5. Division Property of Equality
6. x = 8
6. Simplify
Mathematics
1 answer:
Kamila [148]4 years ago
8 0

Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

Step-by-step explanation:

The reason given to go from :

2 (3x +4) = 56  to 6x + 8 = 56

is NOT "Multiplication Property of Equality" because one is not multiplying both sides of the equality by a number. The property that is being used is the Distributive Property on the left side of the equation in order to remove the grouping symbols (parenthesis) performing the implied multiplication of the external factor times each term of the binomial in parenthesis.

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Write the expression in factored form. X^2+3x+xy
sergey [27]

Answer:

Factored form of x^2+3x+xy is x(x + 3 + y)

Step-by-step explanation:

x^2+3x+xy

Factor form ;

= x (x + 3 + y)

8 0
4 years ago
A box is 120cm long and 25cm wide. What is the longest length of a ski pole that could be packed to lie flat in the box if they
vovangra [49]

Answer:

The longest ski pole to fit would lie diagonally. The length of the diagonal can be found by the Pythagorean theorem.

d=sqrt(1202+252)

d ~= 122.58 cm

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
Use the graph to answer the question. Find the slope
Liula [17]
We can take the two points given and plug them into the slope formula.

\sf~m=\dfrac{y_2-y_1}{x_2-x_1}

(-3, 3), (1, -5)
x1  y1  x2 y2

\sf~m=\dfrac{-5-3}{1-(-3)}

Subtract:

\sf~m=\dfrac{-8}{4}

Divide:

\sf~m=-2
8 0
4 years ago
The temperature outside dropped 13°F in 7 hours. The
Shkiper50 [21]

Answer:

15 degrees Fahrenheit

Step-by-step explanation:

2+13=15

or 13+2=15

4 0
3 years ago
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