Similar figures always have .....?

DedPeter [7]

F(x) = 1/(x+2) & g(x) = x/(x-3)

(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)

7 0

2 years ago

You want to estimate the probability that a lightbulb of a famous brand will last more than 6.500 hours. You choose 10,000 bulbs

brilliants [131]

Answer/Step-by-step explanation:

(a) The likelihood function to estimate this probability can be written as:

mat[1000, 9800]p9580(1 - p)420

(b) The value of the maximum likelihood estimate of the probability 0.958(By taking log of expression in (a) above)

(c) when the true probability is 98%, then it implies that 9800 of 10,000 bulbs did last over 6500hours.

Therefore, the likelihood is p(9800) = mat[10000, 9800]p9800(1 - p)200

(d) Method of moments estimate is the estimation of all the parameters of the population sample.

(e) The statement is FALSE because estimates by the method of moments are not necessarily sufficient statistics, because sometimes fail to take into account all relevant information in the sample. As in the above question

4 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

Sally's summer punch recipe is a combination of lemonade and fruit punch. Sally uses 6 cups of lemonade for every 8 cups of frui

disa [49]

Answer:

August made the recipe using the correct ratios

Step-by-step explanation:

we know that

Sally uses 6 cups of lemonade for every 8 cups of fruit punch

so

using proportion

Find out the number of cups of fruit punch for 15 cups of lemonade