Similar figures always have .....?

2 answers:

5 0

Answer: Similar figures are always the same shape, but not the same size. They have equal angles but not equal side lengths. Check out a big square and a small square. They're both squares because they have four sides and four equal angles, but the sides aren't the same length.

Step-by-step explanation:

erma4kov [3.2K]3 years ago

5 0

Similar figure always have the same shape but different sizes

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The smiths want to fence their square garden, which has an area 256 square meters.

diamong [38]

The answer s=16 answer 48

6 0

2 years ago

Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9

NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$