While I'm unsure what the word choices were, his claim is likely to be true.
Since he claims the probability of heads is 40%, that should be what we see in an experiment. 0.38 is very close to 0.40, or 40%, so this is true. Therefore his claim is likely to be true, and the probability of tails should be about 60%.
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
19 because 1 ten = 10 ones and 9 one plus 10 ones equals 19 altogether
The true statement is that only line A is a well-placed line of best fit
<h3>How to determine the true statement?</h3>
The scatter plots are not given. However, the question can still be answered
The features of the given lines of best fits are:
<u>Line A</u>
- 12 points in total
- Negative correlation
- Passes through the 12 points with 6 on either sides
<u>Line B</u>
- 12 points in total
- Positive correlation
- Passes through the 12 points with 8 and 4 in either sides
For a line of best fit to be well-placed, the line must divide the points on the scatter plot equally.
From the given features, we can see that line A can be considered as a good line of best fit, because it divides the points on the scatter plot equally.
Read more about line of best fit at:
brainly.com/question/14279419
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