A quantity y varies inversely with the square of x. If y=8 when x=3, find y when x is 4
1 answer:
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The required diagram is attached in the picture below :
Answer:
15.05 miles
2 :09:12
5 hours 19 minutes 18 seconds
Step-by-step explanation:
Given :
28/4/18:
Time : 1 :03 : 25
Fastest mile = 02 : 25
Distance = 15.05 miles
03/5/18:
Time : 2:06: 41
Fastest mile = 02 : 53
Distance = 28.70 miles
08/5/18:
Time : 2 :09:12
Fastest mile = 02 : 45
Distance = 26.39 miles2
1.) shortest distance cycled :
From the data:
15.05 < 26.39 < 28.70
Shortest distance cycled = 15.05 miles
The longest the cycled:
1 :03 : 25 < 2:06: 41 < 2 :09:12
Longest = 2 :09:12
Total cycling time :
1 :03 : 25 + 2:06: 41 + 2 :09:12
(1 + 2 + 2)= 5 hrs
(03 + 06+ 09) = 18 minutes
(25 + 41 + 12) = 78 seconds = 1 minute 18 seconds
18 minutes + 1 minute = 19 minutes
Total = 5 hours 19 minutes 18 seconds
19. It notes or hints to using the quadratic formula because the equation can not be solved by factoring alone. Thus you must use the quadratic formula.
A=-16 B=25 C=3
It is so hard to type a normal equation let alone one of the quadratic formula so I will just attach a picture instead.
However you will end up getting two roots/zeros/x-intercepts of -0.11 and 1.67.
However since it is an application question asking for answers only in the first quadrant you must choose the positive x-intercept.
Therefore the water balloon will land at 1.67 seconds.
20. This question is very simple as it asks you to find a height at a given time. You simply put the given time (1second) into the equation and get your answer.
h=-16(1)^2+25(1)+3
h=12
Also don't mind my little scribble there. :)
A=-16 B=25 C=3
It is so hard to type a normal equation let alone one of the quadratic formula so I will just attach a picture instead.
However you will end up getting two roots/zeros/x-intercepts of -0.11 and 1.67.
However since it is an application question asking for answers only in the first quadrant you must choose the positive x-intercept.
Therefore the water balloon will land at 1.67 seconds.
20. This question is very simple as it asks you to find a height at a given time. You simply put the given time (1second) into the equation and get your answer.
h=-16(1)^2+25(1)+3
h=12
Also don't mind my little scribble there. :)