Answer:
- output = ""
- for i in range(7):
- if(i % 3 == 0):
- for i in range(5):
- output+= "*"
- output += "\n"
- else:
- for i in range(2):
- output += "* "
- output += "\n"
-
- print(output)
Explanation:
The solution code is written in Python 3.
Firstly, create a output variable that holds an empty string (Line 1).
Create an outer loop that will loop over 7 times to print seven rows of stars (Line 2). In row 0, 3 and 6 (which are divisible by 3) will accumulate up to 5 stars using an inner loop (Line 4-5) whereas the rest of the row will only print two stars with each start followed by a single space (Line 8-9) using another inner loop.
At last, print the output (Line 12).
Answer:
<em>C++</em>
///////////////////////////////////////////////////////////////////////////////////////////
#include <iostream>
using namespace std;
//////////////////////////////////////////////////////////////////
class QuadraticEquation {
int a, b, c;
public:
QuadraticEquation(int a, int b, int c) {
this->a = a;
this->b = b;
this->c = c;
}
////////////////////////////////////////
int getA() {
return a;
}
int getB() {
return b;
}
int getC() {
return c;
}
////////////////////////////////////////
// returns the discriminant, which is b2-4ac
int getDiscriminant() {
return (b*2)-(4*a*c);
}
int getRoot1() {
if (getDiscriminant() < 0)
return 0;
else {
// Please specify how to calculate the two roots.
return 1;
}
}
int getRoot2() {
if (getDiscriminant() < 0)
return 0;
else {
// Please specify how to calculate the two roots.
return -1;
}
}
};
//////////////////////////////////////////////////////////////////
int main() {
return 0;
}
