Answer:
Through after school programs
Explanation:
Under represented and under resourced students can be better engaged in STEM programs through the establishment of after school state of the arts learning centres that can augment for the vacuum in the regular school system.
In such programs, the use of technological platforms with an integrated electronic learning system is necessary, because it avails the students the opportunity to brace up with the evolving impact of information technology to learning and personal developments.
Secondly, the use of immediate resources within the reach of these under privileged and under resourced students is a necessity. for example, a student in a rural community could start become more engage in engineering designs, building technology, instrumentation and architecture through the use of disposed cartons used to construct buildings, cars etc.
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
The instructions that he microprocessor can execute each
second if the assembly line is present will be depending on the workload and
the architecture’s core because it is all depending on the speed of the CPU and
the multiplier that it acquires.
Explanation:
Explanation:
RSA encryption is performed by calculating C=M^e(mod n).
However, if n is much larger than e (as is the case here), and if the message is not too long (i.e. small M), then M^e(mod n) == M^e and therefore M can be found by calculating the e-th root of C.
Answer:
ppl
Explanation:
asfafgdffsghsdfghdgsghdfghtrbd54445 ddfgg
