I think that the sum will always be a rational number
let's prove that
<span>any rational number can be represented as a/b where a and b are integers and b≠0
</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....
<span>so, 2 rational numbers can be represented as
</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)
their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd
1. the numerator and denominator will be integers
2. that the denominator does not equal 0
alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer
now the denominator
that is just a product of 2 integers so it is an integer
<span>2. we originally defined that b≠0 and d≠0 so we're good
</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
Answer: 8 (The second option).
Step-by-step explanation:
1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.
2. The lenght XY will be twice the lengt XO or YO.
3. Let's calclate XO as following:

4. Then, XY is:

Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
10 oranges
Step-by-step explanation:
4 oranges are needed to make one cup. 2 cups is 8 oranges and 1/2 cup is 2 oranges
Answer:
y = -2x + 5
Step-by-step explanation:
y=
-3
Slope of this line m₁ = 1/2
Slope of the line perpendicular to this line = m₂
m₁ *m₂ = -1
m₂ = -1 *2/1 = -2
Slope = -2; (1,3)
y- y₁ = m(x-x₁)
y - 3 = -2(x - 1)
y - 3 = -2x + 2
y = -2x +2 +3
y = -2x + 5