Answer: 50 words per minute
Step-by-step explanation:
<u>250</u> <em>words</em> per <u>5</u> <em>minutes</em> <em>DIVIDE BOTH NUMBERS BY 5</em>
50 words per 1 minute
Step-by-step explanation:
The space comprising all possible outcomes (sample space) is represented by the 6×66×6 matrix formed by the possible pairs representing the outcome of dice:
From the above sample space, there are six events wherein the first die is 44 (all elements of the fourth row in the matrix). That is, n(F)=6n(F)=6. Moreover, there are six events wherein doubles are rolled (all diagonal elements in the matrix). That is, n(D)=6n(D)=6. The result (4,4)(4,4) is the intersection of both events. That is, n(D∩F)=1n(D∩F)=1.
Therefore, the possibility/probability that the first die is 4 or that doubles are rolled is computed as follows:
P(D∪F)=P(D)+P(F)−P(D∩F)=n(D)n(S)+n(F)n(S)−n(D∩F)n(S)=636+636−136=1136P(D∪F)=P(D)+P(F)−P(D∩F)=n(D)n(S)+n(F)n(S)−n(D∩F)n(S)=636+636−136=1136
16) 9y+2r If she bought 1 dog toy and 2 treats: 9(1)+2(2)= 13
17) 5n-3n= 2n
17-2+7= 22 Combine like terms
2n+22 Write out expression
2(8)+22= 38 Plug in 8.
Answer: 2n+22; 38
18) 5h^3 h represents the # of weeks; Find # of tickets sold in 3 weeks:h=3
5(3)^3 plug in 3
5(27) PEMDAS; Exponents first; 3*3*3= 27
Answer: 135
19) It is true
If d=2, 5(2)*5(2)*5(2)= (5*2)^3
10*10*10=(10)^3
1,000=1,000
Answer:
see below
Step-by-step explanation:
We need to find the diameter of the square
We can find this using the Pythagorean theorem
a^2+b^2 = c^2 where the legs are 7 and 7 and the diameter is c
7^2 +7^2 = c^2
49+49 = c^2
98 = c^2
Taking the square root of each side
sqrt(98) = sqrt(c^2)
9.899494937 = c
Since 9.9 is less than 11 which is the diameter of the circle it will never touch the circle.
Since the longest part of the square is less than the diameter of the circle, the square will fit inside the circle without touching
Answer: x = 0
<u>Step-by-step explanation:</u>
4(7 - 3x) = 7(4 - 2x)
28 - 12x = 28 - 14x <em>distributed</em>
28 + 2x = 28 <em>added 14x to both sides</em>
2x = 0 <em>subtracted 28 from both sides</em>
x = 0 <em>divided both sides by 2</em>
