Answer:
The Consecutive number are 46 , 47 and 48 having sum as 141
The smallest number is 46
Step-by-step explanation:
• A consecutive numbers means number are in a sequence and are one after the another !
e.g. n , (n+1). Or 1 , 2 are consecutive numbers
• A consecutive even numbers differ by 2 because all even numbers are divisible by 2 !
• If the number is divisible by x we must had taken number as n , ( n + x ) ,
( n + 2x )
• Let the numbers be ( n - 1 ) , n and
( n + 1 )
Given ,the sum of numbers is 141
n - 1 + n + n + 1 = 141
3n = 141
n = 141/3
n = 47
So, the numbers are
n- 1 = 47 - 1 = 46
n = 47
n + 1 = 48
And , the smallest number is 46
• Verification :-
46 + 48 + 47 = 141
Which satisfies the given condition !!
Hence , verified !!
