Question

The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?

Answer 1

Answer:

$||\overrightarrow{v}||\approx14.64$

Step-by-step explanation:

The magnitude of a vector $\displaystyle \overrightarrow{v}=\langle x,y\rangle$ is $||\overrightarrow{v}||=\sqrt{x^2+y^2}$, which essentially describes the length of the vector itself between the initial and terminal points:

$||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64$