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Mumz [18]
3 years ago
14

Individual bottles of water are filled by a machine at a factory with an amount of water that is approximately normal with a mea

n of 505\,\text{mL}505mL505, start text, m, L, end text and a standard deviation of 10\,\text{mL}10mL10, start text, m, L, end text. A random sample of 161616 bottles is selected for a quality inspection. What is the probability that the mean amount of water in these 161616 bottles \bar x x ˉ x, with, \bar, on top is within 5\,\text{mL}5mL5, start text, m, L, end text of the population mean?
Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer:

P(500<  xˉ <510)≈0.95

Step-by-step explanation:

Khan Academy

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Solve for x<br> 6x + 9 &lt; 63
ZanzabumX [31]

Answer:

x < 9

Step-by-step explanation:

Given inequality:

6x + 9 < 63

Subtract 9 from both sides:

⇒ 6x + 9 - 9 < 63 - 9

⇒ 6x < 54

Divide both sides by 6:

⇒ 6x ÷ 6 < 54 ÷ 6

⇒ x < 9

3 0
2 years ago
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stephanie and jenny each improved their yards by planting rose bushes and geraniums. they bought their supplies from the same st
galina1969 [7]

Answer:

The cost of one rose is $11., and the cost of one geranium is $5.

Step-by-step explanation:

The cost of one rose bush and one geranium can be determined by the use of simultaneous equation. Let the cost of a rose bush be represented by x, and the cost of one geranium by y.

So that,

13x + y = 148 .............. 1

9x + 14 y = 169 ............... 2

From eqaution 1,

y = 148 - 13x ............... 3

substitute the value of y in equation 2

9x + 14(148 - 13x) = 169

9x + 2072 - 182x = 169

2072 - 169 = 182x - 9x

1903 = 173x

x = \frac{1903}{173}

  = 11

x = 11

substitute the value of x in equation 3

y = 148 - 13x

  = 148 - 13(11)

  = 148 - 143

y = 5

x = 11, y = 5

Thus, the cost of one rose is $11., and the cost of one geranium is $5.

3 0
3 years ago
If alpha and beeta are the zeroes of 3x^2-5x-2, then evaluate alpha cube beeta + alpha beeta cube
I am Lyosha [343]
1 I think is the answer I hop it helped.
4 0
4 years ago
P(x)equals=​R(x)minus−​C(x). Given ​R(x)equals=59 x minus 0.3 x squared59x−0.3x2 and Upper C left parenthesis x right parenthesi
Deffense [45]

Answer:

P(x)=-0.3x^2+56x-14  

Step-by-step explanation:

The given functions are

R(x)=59x-0.3x^2

C(x)=3x+14

It is given that

P(x)=R(x)-C(x)

Substitute the values of given functions in the above equation.

P(x)=59x-0.3x^2-(3x+14)

P(x)=59x-0.3x^2-3x-14

Combine like terms.

P(x)=-0.3x^2+(59x-3x)-14

P(x)=-0.3x^2+56x-14  

Therefore, the required function is P(x)=-0.3x^2+56x-14   .

4 0
3 years ago
Paul jogged 3.25 miles, rick jogged 3 1/3 miles and sean jogged 3 1/8 miles. list the boys from least to greatest distance jogge
Novosadov [1.4K]

Answer:

Sean jogged 3.125, Paul jogged a distance of 3.25, Rick jogged 3.33

Step-by-step explanation:

make the fractions into decimals once they are in decimal form you cna then go and place them into the correct order.

3 0
3 years ago
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