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Mumz [18]
3 years ago
14

Individual bottles of water are filled by a machine at a factory with an amount of water that is approximately normal with a mea

n of 505\,\text{mL}505mL505, start text, m, L, end text and a standard deviation of 10\,\text{mL}10mL10, start text, m, L, end text. A random sample of 161616 bottles is selected for a quality inspection. What is the probability that the mean amount of water in these 161616 bottles \bar x x ˉ x, with, \bar, on top is within 5\,\text{mL}5mL5, start text, m, L, end text of the population mean?
Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer:

P(500<  xˉ <510)≈0.95

Step-by-step explanation:

Khan Academy

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Alenkinab [10]
<h2>Answer:</h2>

y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function

<h2>Step by step solution:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of f is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find f^-{1}(x):

f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

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Step-by-step explanation:

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Andreas93 [3]

Answer:

x > 2

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Step-by-step explanation:

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