Suppose we want to choose 3 letters, without replacement, from the 4 letters A, B, C, and D.

1 answer:

ioda2 years ago

3 0

Answer:A) 24 waysB) 4 waysStep-by-step explanation:a) permutation occurrs when order of choices matters.N = 4P3 = 4!/(4-3)! = 4!/1!N = 24 waysb) combination occurs when order of choices doesn't matter.N = 4C3 = 4!/3!(4-3)! = 4!/3!(1!)N = 4 ways

Step-by-step explanation:

a) permutation occurrs when order of choices matters.N = 4P3 = 4!/(4-3)! = 4!/1!N = 24 waysb) combination occurs when order of choices doesn't matter.N = 4C3 = 4!/3!(4-3)! = 4!/3!(1!)N = 4 ways(hope this helps:)

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