Check the picture below.
so let's use the law of sines then
![\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1.9}{sin(Z)}~~ = ~~\cfrac{XZ}{sin(Y)}\implies \cfrac{1.9}{sin(89^o)}~~ = ~~\cfrac{XZ}{sin(70^o)}\implies \cfrac{1.9\cdot sin(70^o)}{sin(89^o)}=XZ \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7BLaw%20of%20sines%7D%20%5C%5C%5C%5C%20%5Ccfrac%7Bsin%28%5Cmeasuredangle%20A%29%7D%7Ba%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20B%29%7D%7Bb%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20C%29%7D%7Bc%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B1.9%7D%7Bsin%28Z%29%7D~~%20%3D%20~~%5Ccfrac%7BXZ%7D%7Bsin%28Y%29%7D%5Cimplies%20%5Ccfrac%7B1.9%7D%7Bsin%2889%5Eo%29%7D~~%20%3D%20~~%5Ccfrac%7BXZ%7D%7Bsin%2870%5Eo%29%7D%5Cimplies%20%5Ccfrac%7B1.9%5Ccdot%20sin%2870%5Eo%29%7D%7Bsin%2889%5Eo%29%7D%3DXZ%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
quick observation, the picture of the triangle is very misleading, since those angles as drawn are not good representers of the angles values.
Answer: y=x+3.5
The function of the original equation (the data table) is y=1/2x+3.5
So 1/2 times 2 is 1 and the y intercept (the initial value) is the same! I hope I helped
Answer:
w=40
Step-by-step explanation:
Let's solve your equation step-by-step.
w−8=32
Step 1: Add 8 to both sides.
w−8+8=32+8
w=40
Day 1: 8km=4.97miles
Day 2: 10miles=16.09km
Day 3: 9miles=14.4km
9.6km=5.9miles
I really hope this helps! Not really sure what exactly the answer you are looking for is but this should help you figure it out
