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3 years ago

Factor 64b-16c to identify the equivalent expressions. *

Mathematics

1 answer:

scoray [572]3 years ago

5 0

Answer:

The factored form of this would be 16(4b - c)

Step-by-step explanation:

In order to find this, look for the greatest common factor of 16 and 64. You can do this by listing out their factors. Once this is done and we identify 16 as the GCF, we can then put that on the outside of the parenthesis and divide all the terms inside by that number.

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I need help i don't get it !!!!!

joja [24]

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 30 = x/8

8 sin 30 =x

8 (1/2) = x

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3 years ago

Read 2 more answers

If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable

kkurt [141]

Answer:

The answer is " $\frac{26}{7}$ "

Step-by-step explanation:

The whole question can be found in the file attached.

$\to x + \frac{5}{7} = \frac{31}{7}\\\\$

Subtracting the $\frac{5}{7}$ from both sides of the equations:

$\to x +\frac{5}{7} - \frac{5}{7} = \frac{31}{7} - \frac{5}{7} \\\\$

$= \frac{31-5}{7} \\\\= \frac{26}{7} \\\\$

5 0

3 years ago

I WILL MARK YOU THE BRAINLIEST IF YOU ANSWER THIS CORRECTLY WITH WORK

saul85 [17]

Answer:

Students on Honor Roll had no advantage to get the Science class requested. It was a fair class assignment. In fact No Honor Roll students had advantage over honor Roll Students in obtaining Science Class as requested.

Step-by-step explanation:

Here let us streamline the information we are given one by one

1.) Honor Roll

Get Requested Science Class : 64

Did Not get Requested Science Class : 80

Total : 144

Percentage of Honor Roll Students getting Science class as requested =

$\frac{64}{144}$

= 44.44%

2.) No Honor Roll

Get Requested Science Class : 315

Did Not get Requested Science Class : 41

Total : 356

Percentage of Non Honor Roll Students getting Science class as requested $= \frac{315}{356}$

= 88.8%

By observing the above result , we can assume that Honor Roll students did not have any advantage over non Honor Roll students in getting Science Class as they requested.

3 0

3 years ago

Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day

MaRussiya [10]

Answer:

4) 0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0

3 years ago

Write the quadratic equation whose roots are 1 and -2, and whose leading coefficient is 3.

kirill115 [55]

Answer:

See below

Step-by-step explanation:

The quadratic equation in factored form:

a(x - α)(x - β), where a- leading coefficient, α and β - roots

We have:

a = 3, α = 1, β = -2

Substitute them to get:

3(x - 1)(x + 2)

Converting this into standard form:

3(x - 1)(x + 2) =
3(x² + x - 2) =
3x² + 3x - 6

3 0

2 years ago