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1 year ago

14

How do I do this question: Six numbers have been left to the final door. Those numbers are: 6,2,3,3,2,2. Fill in the following b

lanks, and use those 6 digits to make the largest number possible. Enter that number (without the comma) to escape!

1 answer:

ASHA 777 [7]1 year ago

5 0

Answer:

633222

Step-by-step explanation:

just put them in order from biggest - smallest

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Distribute.<br><br> 1/2 (8x - 16)

Kitty [74]

Answer:

b. 4x-8

Step-by-step explanation:

1/2 x(8x-16)

= 1/2(8x) - 1/2 (16)

=4x - 8

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2 years ago

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kupik [55]

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6

Step-by-step explanation:

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3 years ago

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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3 years ago

Eric jogged 31/4 miles on monday 5 5/8 miles on tuesday and 8 miles on wensday .suppose he continues the pattern for the remaind

Troyanec [42]

The is increasing by 2 3/8
So the answer is 12 3/4 miles on Friday

Hope this helps :)

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3 years ago