Question

A baseball player has a batting average of 0.25. What is the probability that he has exactly 2 hits in his next 7 at bats

Answer 1

Answer:

The probability that he has exactly 2 hits in his next 7 at-bats is 0.3115.

Step-by-step explanation:

We are given that a baseball player has a batting average of 0.25 and we have to find the probability that he has exactly 2 hits in his next 7 at-bats.

Let X = Number of hits made by a baseball player

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,......$

where, n = number of trials (samples) taken = 7 at-bats

            r = number of success = exactly 2 hits

            p = probability of success which in our question is batting average

                   of a baseball player, i.e; p = 0.25

SO, X ~ Binom(n = 7, p = 0.25)

Now, the probability that he has exactly 2 hits in his next 7 at-bats is given by = P(X = 2)

          P(X = 2) =  $\binom{7}{2}\times 0.25^{2} \times (1-0.25)^{7-2}$

                        =  $21 \times 0.25^{2} \times 0.75^{5}$

                        =  0.3115