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Reika [66]
3 years ago
12

Use the points (2, 45) and (8, 90) to find the slope and y-intercept of the trend line for the data comparing hours studied to t

est scores.
m =
b =
Mathematics
1 answer:
NARA [144]3 years ago
4 0

Answer:

m= 7.5

b= 30

Step-by-step explanation:

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I NEED HELP PLZ!!!! It’s important!
rewona [7]

Answer: 24x^3 sqrt5x -4x^3 sqrt10x

Step-by-step explanation:

Show in the photo attached.

3 0
3 years ago
Read 2 more answers
Is 2 to the power of 3 bigger then the square root of 5?
BARSIC [14]

Answer:

Yes.

Step-by-step explanation:

Let's write out each problem:

\sqrt{5} = 2.3

2^3 = 8

Now that we have both answers to each expression, we can tell that 2^3, in fact, is larger than the square root of 5.

So your answer is, "Yes, 2^3 is bigger than the square root of 5.

Feel free to give brainlest.

Have an amazing day!

6 0
3 years ago
-k(-4k^2+k+2) Best one and simplest one gets the brainliest, I'm In a rush.
sasho [114]

Answer:

4k^3 - k^2 - 2k

Step-by-step explanation:

-k * -4k^2 = 4k^3

-k * k = -k^2

-k * 2 = -2k

4k^3 - k^2 - 2k

4 0
3 years ago
Read 2 more answers
Help please. I need the answer.
Deffense [45]
Create and solve an appropriate equation:  Maria's earnings = Liam's earnings

                                                                       0.20x                 = $625+0.10x.

Find x.

0.10x = $625; thus, x = $6250.  At this level of food sales, these two people earn the same amount.
3 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
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