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ivolga24 [154]
2 years ago
8

If the simple interest on ​$7000 for 10 years is ​$6300​, then what is the interest​ rate? I will pick branliest answer with the

most thorough explanation. Please help. If you do, thanks for helping! Use the picture below for question.

Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

0.09

Step-by-step explanation:

So if you use the Simple interest equation it will begin with:
Interest total = Initial Amount of money x Interest rate per year x Years money is invested for.

Then substitute the values you have been given so:

$6300 = 7000 x Interest rate per year x 10.

This is simplifies to 6300 = 70,000 x Annual Interest rate

You can rearrange this to find the annual interest rate by dividing by 70,000:
\frac{6300}{70000} = Interest\ rate

Simplifying this would be:
\frac{63}{700}\\ = Interest rate.

The interest rate is 0.09.

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Help me with this lol value of( 2^3)^2
ss7ja [257]

Answer:

64

Step-by-step explanation:

first, we'll start with the value inside the parenthesis, which is 2³

2³ means to multiply 2 by itself 3 times

so it would be

2×2×2=8

which then means that the expression is now (8)²

now we need to do (8)², which is to multiply 8 by itself twice

8*8=64

hope this helps!

6 0
3 years ago
Which statement best reflects the solution(s) of the equation?
Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0

Now, factoring the term:

x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

5 0
4 years ago
Which point is a solution to the inequality shown in this graph? (3,-1) (-3,-3)
Ne4ueva [31]

Answer: try c (1,5)

Step-by-step explanation: hey eri-chan

5 0
3 years ago
9(42) - 9(4) = 9(30) + 9 (___)
OverLord2011 [107]

Answer:

8

Step-by-step explanation:

378-36-270=9x

72=9x

72÷9=9x÷9

8=x

X=8

5 0
3 years ago
Write a word phrase that can be represented by b-6
Bess [88]
Six less than "b"
i think this would be the answer
good luck!!
7 0
3 years ago
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