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3 years ago

The zoo downtown has 9 times as many monkeys as elephants. They have 60 animals all together. How many elephants are there?

2 answers:

6 0

Answer: There’s technically no answer to this question, unless you specify that the zoo only has monkeys and elephants. If the zoo has more than two types of animal then the ratio doesn’t help because there are unknown variables.

However, if we knew that the zoo only has monkeys and elephants, then:

E = number of elephants

M = number of monkeys

M=9E

M + E = 60

9E+E= 60

10E = 60

E = 6

There are 6 elephants (and 54 monkeys).

dolphi86 [110]3 years ago

3 0

Answer:

Step-by-step explanation:

e = number of elephants

9 times as many monkeys as elephants

m = 9e

------------------------

60 animals all together

e + m = 60

e + 9e = 60

Combine like terms

10e = 60

Divide both sides by 10

e = 6

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Answer:

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 252$

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The second sample size is $n_2 = 476$

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$\^ p _1 = \frac{k_1 }{ n_1 }$

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Generally the second sample proportion is mathematically represented as

$\^ p _2 = \frac{k_2 }{ n_2 }$

=> $\^ p _2 = \frac{20 }{ 476}$

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The null hypothesis is $H_o : p_1 - p_2 = 0$

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$z = \frac{ \^ p_1 - \^ p_2 - ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1 } + \frac{\^ p_2 (1-\^ p_2)}{ n_2 } } }$

=> $z = \frac{ 0.071 - 0.042 - 0 }{ \sqrt{\frac{0.071 (1-0.071)}{ 252 } + \frac{0.042 (1-\^ 0.042)}{ 476 } } }$

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Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > 1.56 )$

=> $p-value = 2 * 0.05938$

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From the value obtained we see that $p-value > \alpha$ hence

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Fail to reject the null hypothesis

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