Answer:
first we need to substitute g(t) value in h(t) value and then evaluate the expression as follows :
h(g(t))=3(t-1)²+4(t-1).
by solving
h(g(t))=3(t²+1-2t)+4t-4
h(g(t))=3t²-2t-1 will.be the final answer
Subtracting whole numbers does not include subtracting negative numbers, whereas when subtracting integers you can include negative numbers.
Step-by-step explanation:





<u>Let us assume that:</u>

<u>Therefore, the equation becomes:</u>






<u>Now substitute the value of u. We get:</u>


<u>Therefore:</u>


★ <u>Which is our required answer.</u>

(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²
a² - b² = (a + b)(a - b)
(a + b)³ = a³ + 3ab(a + b) + b³
(a - b)³ = a³ - 3ab(a - b) - b³
a³ + b³ = (a + b)(a² - ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
(x + a)(x + b) = x² + (a + b)x + ab
(x + a)(x - b) = x² + (a - b)x - ab
(x - a)(x + b) = x² - (a - b)x - ab
(x - a)(x - b) = x² - (a + b)x + ab