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2 years ago

Part A

Mathematics

1 answer:

kap26 [50]2 years ago

4 0

Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1

<h3>How to reflect the polygon?</h3>

The coordinates are given as:

F(2, – 1), G(5,2), H(8, 3), and I(6, 0)

The line of reflection is given as:

y = -1

To reflect the line, we apply the following rule of reflection

(x,y) $\to$ (x,-y-2)

So, we have the following coordinates of the image

F' = (2, – 1)

G' = (5,-4)

H' = (8, -5)

I' = (6, -2)

See attachment for the image of the reflected polygon

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Use Words,Pictures or Numbers, make a Math Arguement.

Pavel [41]

13, 6+7=13 thats my answer :D

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4 years ago

Whats the Axis of Symmetry? willing to give 15 points !!

nydimaria [60]

The axis of symmetry of a parabola in the form

$y=ax^2+bx+c$

is a vertical line

$x=k$

where k is the x coordinate of the vertex of the parabola.

The x coordinate of the vertex of the parabola is given by

$-\dfrac{b}{2a}$

which in your case is

$-\dfrac{-6}{2\cdot \frac{1}{4}}=\dfrac{6}{\frac{1}{2}}=6\cdot 2=12$

So, the axis of symmetry is the line x=12.

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3 years ago

3x^2-y^3-y^3-z if x=3, y=-2, and z=-5

Serggg [28]

$3(3)^2-(-2)^3-(-2)^3-(-5) = 48$

48 is the answer.

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3 years ago

Read 2 more answers

NEED THE ANSWER ASAP FOR MY TEST PLZ

Andreyy89

Answer:

The slope intercept form of a line is: y=mx+b.

Step-by-step explanation:

your answer is (a)

gimme brainliest

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3 years ago

Read 2 more answers

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago