3 years ago

Can someone please click on my profile and answer my history question please!

Mathematics

1 answer:

ANEK [815]3 years ago

3 0

Answer:

yeah sure

Step-by-step explanation:

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85% of £30

sergij07 [2.7K]

Re read the question again just in case, try and put £25.50
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3 years ago

What is [(7x^3)(y^2)]^2/7 in radical form?

GuDViN [60]

Remember
$x^ \frac{m}{n} = \sqrt[n]{x^m}$
and
$(zy)^m=(z^m)(y^m)$
and
(x^m)^n=x^(mn)

so
$((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}$ =
$\sqrt[7]{((7x^3)^2(y^2)^2)}$ =
$\sqrt[7]{((7^2x^6)(y^4))}$ =
$\sqrt[7]{((49x^6)(y^4))}$ =
$\sqrt[7]{49x^6y^4}$

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3 years ago

HELP THIS IS DUE SOON!<br><br> find the error!

Rudik [331]

Answer:

Step 1

Step-by-step explanation:

they were supposed to multiply 2x by 4 and -1 by 4 but they only multiplied 2x by 4.

3 0

3 years ago

Read 2 more answers

If the probability of a win is 0.5 and the probability of a draw is 0.3, what is the probability of a loss?