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Dima020 [189]
4 years ago
9

Jefferson high school has 100 less than 5 times As many Students as Taft high school how many students are at Jefferson high sch

ool if Taft high school has 300 students​

Mathematics
1 answer:
Rzqust [24]4 years ago
7 0

Answer:

1,400

Step-by-step explanation:

300x5=1,500 and 1,500-100=1,400

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Timothy has read 8/9 of the book Holes. Tara has read 2/3 of the book. Phillip reads 4/5 of the book. who read the most
nevsk [136]

Answer: Timothy

Step-by-step explanation:

8/9=0.8888888889

2/3=0.6666666667

4/5=0.8

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3 years ago
At 19:30 Jack lights a campfire. At 22:15 he puts the fire out. Yeah
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3 years ago
The curved part of this figure is a semicircle. What is the best approximation for the area of this figure? 18+12.125π units² 36
andreyandreev [35.5K]

Answer:

18+12.125π units²

Step-by-step explanation:

The diameter of the semicircle can be found by the use Pythagoras theorem.

Δx²+Δy²=d²

Δx=3--1=4

Δy=3--6=9

d²=4²+9²

d=√(16+81)

Area=πr²/2

=π×(√(16+81)/2)²÷2

=[π×(97)/4]/2

=97π/8

=18+12.125π units²

97π/8 is equivalent to 18+12.125π units²

3 0
3 years ago
3x+10+70=180 I'm supposed to find the value of x
liubo4ka [24]
To find the value of x let's make the situation a bit easier

3x+10+70=180
3x+80=180
3x=180-80
3x=100
x = about 33.33
7 0
4 years ago
Read 2 more answers
A website manager has noticed that during the evening​ hours, about 5 people per minute check out from their shopping cart and m
Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is​ made

c) 0.05% probability that seven people make a purchase in the next four ​minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that \mu = 5

a) What model might you suggest to model the number of purchases per​ minute? ​

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is​ made

c) What is the probability that seven people make a purchase in the next four ​minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

0.05% probability that seven people make a purchase in the next four ​minutes

8 0
4 years ago
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