What is the value of 1 x 24

Cooper is grating cheese for his family taco dinner. He grates 1/2 of cheddar cheese and 3/4 cup of monterey jack cheese. How mu

sashaice [31]

Answer:

1 1/4 cup of cheese

Step-by-step explanation:

.5+.75

3 0

4 years ago

A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and r

dsp73

Answer:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

Now we can find the degrees of freedom:

$df=n-1=80-1=79$

Now we can calculate the p value with the alternative hypothesis using the following probability:

$p_v =P(t_{(79)}>2.236)=0.0141$

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if shoppers participating in the loyalty program spent more on average than typical shoppers (120) , the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

Now we can find the degrees of freedom:

$df=n-1=80-1=79$

Now we can calculate the p value with the alternative hypothesis using the following probability:

$p_v =P(t_{(79)}>2.236)=0.0141$

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

3 0

3 years ago

Question 3 please! Thanks.

Ugo [173]

I haven't done this in a while but I think the answer is 16

5 0

3 years ago

Drag each tile to the correct location on the table. Each tile can be used more than once, but not all tiles will be used.

Delvig [45]

Answer: I can help you out just a little this is what I got correct

Step-by-step explanation: