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ryzh [129]
4 years ago
12

The graph of g(x) contains the point (7,12). What point must be on the graph of the function f(x) if g(x) = 2f(x-3)+4?

Mathematics
1 answer:
yulyashka [42]4 years ago
5 0
First take out 2 as a factor
g(x) = 2[f(x-3)+2]


f(x-3) means a shift of +3 in the x direction
+2    means a shift of +2 in the y direction
2[f]   means a stretch of scale factor 2 in the y direction

so (7+3, 2(12+2)) -> (10,28) 
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lisabon 2012 [21]

Answer:

<em>The coordinates of L are (4,5)</em>

Step-by-step explanation:

<u>Partition</u>

Given the points M(-2,-3) R(7,9), we must find a point L(x,y) such that the distance from M to L is double the distance from L to R. This means:

\overline{ML}=2.\overline{LR}

We'll apply that relation on both axes separately:

x_M-x=2(x-x_R)

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Operating:

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Joining like terms:

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Solving:

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Now for the y-axis:

y_M-y=2(y-y_R)

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Operating

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Joining like terms:

3y=15

Solving

y=15/3=5

Thus the coordinates of L are (4,5)

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