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Oksi-84 [34.3K]
2 years ago
11

13 Answer:

Mathematics
1 answer:
Marizza181 [45]2 years ago
4 0

Step-by-step explanation:

13.

132 miles in 3 h = 132miles/3hours = 132/3 miles/h =

= 44 miles/h

so,

how long for 110 miles ?

speed = distance/time

time = distance/speed = 110 miles / 44 miles/h =

= 110/44 h = 55/22 h =

= 5/2 h = 2.5 h

14.

60% = 60/100 = 6/10 = 3/5

15.

300% = 300/100 = 3

16.

116 2/3% = (348 + 2)/3% = 350/3% = 350/3/100 =

= 350/300 = 1 50/300 = 1 1/6

17.

19% = 19/100

18.

3.8% = 3.8/100 = 38/1000 = 19/500

19.

166 2/3% = (498 + 2)/3% = 500/3% = 500/3/100 =

= 500/300 = 5/3 = 1 2/3

20.

4/5 = 0.8 = 80%

21.

7/4 = 1.75 = 175%

22.

1/3 = 0.3333333... ≈ 33.33%

23.

2 = 200/100 = 200%

24.

0.4 = 40%

25.

0.375 = 37.5/100 = 37.5%

26.

80% of 60 = 60×80/100 = 60×4/5 = 48

27.

24% of 65 = 65×24/100 = 65×6/25 = 13×6/5 =

= 15.6

28.

115% of 138 = 138×115/100 = 138×23/20 =

= 69×23/10 = 158.7

29.

18.3% of 74 = 74×18.3/100 = 74×183/1000 =

= 37×183/500 = 13.542 ≈ 13.54

30.

6.5% of 115 = 115×6.5/100 = 115×65/1000 =

= 23×13/40 = 7.475 ≈ 7.48

31.

0.75% of 93 = 93×0.75/100 = 93×75/10000 =

= 93×3/400 = 0.6975 ≈ 0.70

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Let f be the function defined by f(x)=cx−5x^2/2x^2+ax+b, where a, b, and c are constants. The graph of f has a vertical asymptot
Musya8 [376]

Answer:

a) a = 2 and b = -4, b) c = -10, c) f(-2) = -\frac{5}{3}, d) y =  -\frac{5}{2}.

Step-by-step explanation:

a) After we read the statement carefully, we find that rational-polyomic function has the following characteristics:

1) A root of the polynomial at numerator is -2. (Removable discontinuity)

2) Roots of the polynomial at denominator are 1 and -2, respectively. (Vertical asymptote and removable discontinuity.

We analyze each polynomial by factorization and direct comparison to determine the values of a, b and c.

Denominator

i) (x+2)\cdot (x-1) = 0 Given

ii) x^{2} + x-2 = 0 Factorization

iii) 2\cdot x^{2}+2\cdot x -4 = 0 Compatibility with multiplication/Cancellative Property/Result

After a quick comparison, we conclude that a = 2 and b = -4

b) The numerator is analyzed by applying the same approached of the previous item:

Numerator

i) c\cdot x - 5\cdot x^{2} = 0 Given

ii) x \cdot (c-5\cdot x) = 0 Distributive Property

iii) (-5\cdot x)\cdot \left(x-\frac{c}{5}\right)=0 Distributive and Associative Properties/(-a)\cdot b = -a\cdot b/Result

As we know, this polynomial has x = -2 as one of its roots and therefore, the following identity must be met:

i) \left(x -\frac{c}{5}\right) = (x+2) Given

ii) \frac{c}{5} = -2 Compatibility with addition/Modulative property/Existence of additive inverse.

iii) c = -10 Definition of division/Existence of multiplicative inverse/Compatibility with multiplication/Modulative property/Result

The value of c is -10.

c) We can rewrite the rational function as:

f(x) = \frac{(-5\cdot x)\cdot \left(x+2 \right)}{2\cdot (x+2)\cdot (x-1)}

After eliminating the removable discontinuity, the function becomes:

f(x) = -\frac{5}{2}\cdot \left(\frac{x}{x-1}\right)

At x = -2, we find that f(-2) is:

f(-2) = -\frac{5}{2}\cdot \left[\frac{(-2)}{(-2)-1} \right]

f(-2) = -\frac{5}{3}

d) The value of the horizontal asympote is equal to the limit of the rational function tending toward \pm \infty. That is:

y =  \lim_{x \to \pm\infty} \frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x -4} Given

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot 1\right] Modulative Property

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot \left(\frac{x^{2}}{x^{2}} \right)\right] Existence of Multiplicative Inverse/Definition of Division

y =  \lim_{x \to \pm \infty} \left(\frac{\frac{-10\cdot x-5\cdot x^{2}}{x^{2}} }{\frac{2\cdot x^{2}+2\cdot x -4}{x^{2}} } \right)   \frac{\frac{x}{y} }{\frac{w}{z} } = \frac{x\cdot z}{y\cdot w}

y =  \lim_{x \to \pm \infty} \left(\frac{-\frac{10}{x}-5 }{2+\frac{2}{x}-\frac{4}{x^{2}}  } \right)   \frac{x}{y} + \frac{z}{y} = \frac{x+z}{y}/x^{m}\cdot x^{n} = x^{m+n}

y =  -\frac{5}{2} Limit properties/\lim_{x \to \pm \infty} \frac{1}{x^{n}}  = 0, for n \geq 1

The horizontal asymptote to the graph of f is y =  -\frac{5}{2}.

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