The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.
Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation
〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0
==> <em>z</em> - 2 = 0
==> <em>z</em> = 2
Answer:
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Step-by-step explanation:
Answer:
the answer is -6x-y
Step-by-step explanation:
I'm good at math
Answer:
C
Step-by-step explanation:
1. Define word "zeros"
zeros = x-intercepts
2. Find x-intercepts
(-2, 0) and (-4, 0)
x-intercepts = -2, -4 or -4, -2
