Question

The average value of the function y = x² – 1 on [0, 12] is

Answer 1

Answer:

47.

Step-by-step explanation:

1) the rule:

$f_{avr}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx ,$

where a;b are 0 and 12, f(x)=x²-1.

2) according to the rule above:

$f_{avr}=\frac{1}{12-0} \int\limits^{12}_0 {(x^2-1)} \, dx=\frac{1}{12}(\frac{x^3}{3}-x)|^{12}_0=48-1=47.$