Explain how the number of pieces in a whole relates to the size of each piece
2 answers:
Answer:
Let me Demonstrate this by an Example.Suppose there is Paper in the shape of Rectangle which is cut into four equal parts, and the same paper is cut into ten equal parts.
Now when the paper was divided into four parts
Ratio of one part of divided paper to ratio of whole paper
And, the second way, in which the paper was divided into ten parts
Ratio of one part of divided paper to ratio of whole paper
As, number of part of a thing increases, the size of each single divided piece decreases.
I have explained it with the help of diagram also,
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The probability that the tenth person randomly interviewed in that city is the fifth one to own a dog = 0.051
Given,
Consider the interview of a person is a trial.
Lets consider it success if a person owns a dog and consequently , a person without a dog will be a failure.'
Let the random variable X represent the number of persons to be interviewed to get 5 dog owner: in other words, to get 5 successors.
Probability of a success in each trial is p = 0.3. Therefore probability of a failure in each trial is q = 1 - p = 0.7 .
Because trials are independent. X has a negative binomial distribution with parameters k = 5, p = 0.3
P(X =x ) = b(x: k, p) =
where, x = k , k + 1 , k + 2......(1)
Now, Lets find the probability that the tenth person randomly interviewed in that city is the fifth one to own a dog
Using equation (1), we get:
P(X = 10) = b(10: 5, 0.3)
= [(10-1) (5 - 1)]
= [(9)(4)]
= 0.05146
Hence, The probability that the tenth person randomly interviewed in that city is the fifth one to own a dog = 0.051
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