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3 years ago

May I have some help please?

Mathematics

1 answer:

MakcuM [25]3 years ago

6 0

Answer:

If this is solving for a hypotenuse, the answer is 8.

Step-by-step explanation:

a^2 + b^2 = c^2

6^2 b^2 = 10^2

36 + b^2 = 100

100 - 36 = 64

The square root of 64 is 8.

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G(x)=3x^2-5x-9 find g(x+2)

Anna35 [415]

Answer: 3x^2 + 7x -15
I dunno if u want me to factor it tho

7 0

2 years ago

Solve for x . X+9 .. 2x-3 .

nadezda [96]

X + 9 = 2x - 3
-x -x 
 9 = x - 3
 +3 +3
 12 = x

6 0

3 years ago

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single f

irakobra [83]

Answer:

59.049%

Step-by-step explanation:

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws

P(making one free throw) =90%

Therefore:

$P($making 5 consecutive free throws)=P(making 1st) X P(making 2nd) X P(making 3rd)X P(making 4th) X P(making 5th)\\\\=90\%X90\%X90\%X90\%X90\%\\\\=0.9X0.9X0.9X0.9X0.9\\\\=0.59049\\\\=59.049\%$

7 0

3 years ago

The formula for the equation describing a straight line is y = b0 + b1x. the value for b1 in this equation represents the ______

Rasek [7]

Equation of a straight line is normally in the form: y = mx + c.

Where, m and c are constants in which;
m = gradient
c = y-intercept.

Comparing this standard way way of writing the equation of a straight line with the current scenario, this equation can be rewritten as;
y = b1x + b0.

This way, b1 = gradient of the line while b0 = y-intercept.

4 0

3 years ago

The vertices of a square CDEF are C(1,1), D(3,1), E(3,-1) and F(1,-1). What formulas prove that the diagonals are congruent perp

Oxana [17]

To prove that the diagonals are congruent, you need to formula to compute the distance between two points:

$d(A,B) = \sqrt{(A_x-B_x)^2 + (A_y-B_y)^2}$

Using that formula, you may prove that $d(C,E) = d(D,F)$ , which means that the two diagonals have the same length.

To prove that they are perpendicular, you need the formula to compute the slope of a segment. The slope, knowing the enpoints, is given by

$m = \cfrac{\Delta y}{\Delta x} = \cfrac{A_y-B_y}{A_x-B_x}$

You can use this formula to prove that

$m_{CE} = -\cfrac{1}{m_{DF}}$

In fact, if one slope is the opposite of the reciprocal of the other, the two segments are perpendicular.

Finally, to prove that they bisect each other, you first need to find the point where they meet. First of all, you need to find the line the segments lie on: the formula is

$y-y_0 = m(x-x_0)$

where $(x_0,y_0)$ is one of the points belonging to the line, and you already know how to find the slope. Then, you find the point of intersection, say A, by solving the system involving the two lines:

$\begin{cases} y= m_{CE}x+q_{CE}\\ y = m_{DF}x+q_{DF} \end{cases}$

And use again the formula for the distance between two points to prove that

$d(A,C) = d(A,D) = d(A,E) = d(A,F)$

4 0

3 years ago