May I have some help please?
1 answer:
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Answer:
eccentricity; e = 1/7
k = 12
Conic section; Ellipse
Step-by-step explanation:
The first step would be to write the polar equation of the conic section in standard form by multiplying the numerator and denominator by 1/7;
The polar equation of the conic section is now in standard form;
The eccentricity is given by the coefficient of cos theta in which case this would be the value 1/7. Therefore, the eccentricity of this conic section is 1/7.
The eccentricity is clearly between 0 and 1, implying that the conic section is an Ellipse.
The value in the numerator gives the value of k; k = 12
Answer:
a) The half life of the substance is 22.76 years.
b) 5.34 years for the sample to decay to 85% of its original amount
Step-by-step explanation:
The amount of the radioactive substance after t years is modeled by the following equation:
In which P(0) is the initial amount and r is the decay rate.
A sample of a radioactive substance decayed to 97% of its original amount after a year.
This means that:
Then
So
(a) What is the half-life of the substance?
This is t for which P(t) = 0.5P(0). So
The half life of the substance is 22.76 years.
(b) How long would it take the sample to decay to 85% of its original amount?
This is t for which P(t) = 0.85P(0). So
5.34 years for the sample to decay to 85% of its original amount