The product of given expression is ![\frac{1}{15} \text{ or } 0.0667](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B15%7D%20%5Ctext%7B%20or%20%7D%200.0667)
<em><u>Solution:</u></em>
Given that we have to find the product and write it in lowest term
Given expression is:
![\frac{7}{54} \times \frac{27}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B54%7D%20%5Ctimes%20%5Cfrac%7B27%7D%7B35%7D)
Let us first find common factors of numerator and denominator so, thet simplification becomes easier
![54 = 27 \times 3\\\\35 = 7 \times 5](https://tex.z-dn.net/?f=54%20%3D%2027%20%5Ctimes%203%5C%5C%5C%5C35%20%3D%207%20%5Ctimes%205)
Substituting these in above expression, we get
![\rightarrow \frac{7}{27 \times 3} \times \frac{27}{7 \times 5}](https://tex.z-dn.net/?f=%5Crightarrow%20%5Cfrac%7B7%7D%7B27%20%5Ctimes%203%7D%20%5Ctimes%20%5Cfrac%7B27%7D%7B7%20%5Ctimes%205%7D)
Cancel the common factors in numerator and denominator
![\rightarrow \frac{1}{15}](https://tex.z-dn.net/?f=%5Crightarrow%20%5Cfrac%7B1%7D%7B15%7D)
In decimal form, we get
![\rightarrow \frac{1}{15} = 0.0667](https://tex.z-dn.net/?f=%5Crightarrow%20%5Cfrac%7B1%7D%7B15%7D%20%3D%200.0667)
Thus the product of given expression is ![\frac{1}{15} \text{ or } 0.0667](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B15%7D%20%5Ctext%7B%20or%20%7D%200.0667)
Answer:
about $2.54 per pound of sugar
Answer:
x = 5 ![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
Step-by-step explanation:
Hi there!
So, to answer this problem, I'll use the reverse method.
31 - 4 = 27,
So how many times, can 5 go into 27?
The closest factor of 5 to 27 is 25.
5 can go in to 27, 5 times.
Continuing on, there is a 2 left over, so the answer to your question is
x = 5 ![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
5 · 5
- 4 = 31
Let me know if I am incorrect and I will attempt to find the right answer for you.
<em>waffletowne</em>