I bet you're doing the Law of Sines right now. If you use the law of sines you find out that angle A is a 90 degree angle. There is only one triangle you can make with these measurements because if you have one angle of 30 and another of 90, the 3rd angle has to be a 60 degree angle. So it is a special right triangle, 30-60-90
<span><span>the answer is 10<span>x^7</span></span><span>y<span>^2</span></span></span>
Answer:
Jermey is not correct because abouslte value is always postive
Step-by-step explanation:
Answer:
O the circumcenter is equidistant to all three vertices
Step-by-step explanation:
Answer:
Step-by-step explanation:
Perimeter of Square = 40 cm
4*side = 40
side = 40/4
side = 10 cm
Area of shaded region= Area of square - [Area of triangle 1 + Area of triangle 2]
![=[side*side]-[\frac{1}{2}*b*h+\frac{1}{2}*b*h]\\\\=[10*10]-[\frac{1}2}*3*10+\frac{1}{2}*10*6]\\\\=100-[3*5+5*6]\\\\=100-[15+30]\\\\=100-45\\\\=55cm^{2}\\](https://tex.z-dn.net/?f=%3D%5Bside%2Aside%5D-%5B%5Cfrac%7B1%7D%7B2%7D%2Ab%2Ah%2B%5Cfrac%7B1%7D%7B2%7D%2Ab%2Ah%5D%5C%5C%5C%5C%3D%5B10%2A10%5D-%5B%5Cfrac%7B1%7D2%7D%2A3%2A10%2B%5Cfrac%7B1%7D%7B2%7D%2A10%2A6%5D%5C%5C%5C%5C%3D100-%5B3%2A5%2B5%2A6%5D%5C%5C%5C%5C%3D100-%5B15%2B30%5D%5C%5C%5C%5C%3D100-45%5C%5C%5C%5C%3D55cm%5E%7B2%7D%5C%5C)
Percentage = (55/100)*100=55%
