Answer:
Half the age of Carlos four years ago is 2 years more than one-third his current age.
Step-by-step explanation:
We want to write a word problem for the equation.
Let x represent the present age of Carlos.
Four years ago, Carlos was x-4 years.
Half his age four years ago is ½(x-4)
Two years more than one-third his current age is ⅓x+2
14 days = 2 weeks
20weeks : 14 days = 20 weeks : 2 weeks = 20 weeks / 2 weeks = 10:1
hope it helps!
Answer:
<u>For one Necklace you would need...</u>
24 blue beads.
16 white beads.
4 green beads.
Ratio: 24: 16: 4
Step-by-step explanation:
If you quadruple the amount of beads from the original amount (6 : 4: 1), the total beads for that necklace will be 44.
Step 1: 6 x 4 = 24 (amount of blue beads in necklace).
Step 2: 4 x 4 = 16 (amount of white beads in necklace).
Step 3: 1 x 4 = 4 (amount of green beads in necklace).
Now check to see if the total of all types of beads sum up to 44:
Step 4: 24 + 16 + 4 = 44
______________-
There is your answer:
You need 24 blue beads, 16 white beads, and 4 green beads to have a total sum of 44 beads in that one necklace.
Yeeeeeeeeeeeweeeeeeeeeeeeeeee
Ax + By = C form of the given equation is –6x + y = –28.
Solution:
Given equation is y – 2 = 6(x – 5).
To write the equation in Ax + By = C format:
y – 2 = 6(x – 5)
y – 2 = 6x – 30
Add 2 on both sides of the equation.
y – 2 + 2 = 6x – 30 + 2
y = 6x – 28
Subtract 6x from both sides of the equation.
y – 6x = 6x – 28 – 6x
y – 6x = –28
Arrange the terms in the equation.
–6x + y = –28
This is in the form of Ax + By = C.
Here A = –6, B = 1 and C = –28.
