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quester [9]
3 years ago
8

Consider the following pair of equations:

Mathematics
1 answer:
frozen [14]3 years ago
3 0
X+4=y=-2x-2
x+4=-2x-2
add 2x to both side
3x+4=-2
minus 4 both sides
3x=-6
divide 3
x=-2

sub back
y=x+4
y=-2+4
y=2

(x,y)
(-2,2)
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Find the value of x in the isosceles triangle shown below.​
dybincka [34]

USING PYTHAGORAS THEORAM,

x²+3²= 5²

x²+9= 25

x²= 25-9 = 16

x= √16

x= 4

OPTION D

6 0
3 years ago
jane can do a job in 3 hours, while gary can do the same job in 2 hours. if jane works alone for an hour before gary helps her h
Rudiy27

Answer: 2hrs?

Step-by-step explanation: 3-2=1+1 hour she took alone = 2hrs

8 0
2 years ago
Read 2 more answers
Suppose p(a) = 0.40 and p(a 
sveticcg [70]
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

P(A\cup B)+P(A\cap B)=P(A)+P(B)


For parts (a) and (b), you're given everything you need to determine P(B).

For part (c), if A and B are mutually exclusive, then P(A\cap B)=0, so P(A\cup B)=P(A)+P(B). If the given probability is P(A\cup B)=0.55, then you can find P(B)=0.15. But if this given probability is for the intersection, finding P(B) is impossible.


For part (d), if A and B are independent, then P(A\cap B)=P(A)\cdot P(B).
8 0
3 years ago
4(g-1)=24 what is g please help
denis23 [38]

Answer:

G=7

Step-by-step explanation:

4(g-1)=24

4g-4=24

4g=28

g=7

3 0
4 years ago
Read 2 more answers
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
3 years ago
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