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Alex Ar [27]
2 years ago
7

If a 370 KG missile is flying at a speed of 220 m/s , then what is it’s kinetic energy

Physics
1 answer:
lidiya [134]2 years ago
4 0

Answer:

8954000 J

Explanation:

The formula to find kinetic energy is:

<em>Kinetic energy = </em>\frac{1}{2}<em> × mass × (velocity)²</em>

So, Kinetic energy = \frac{1}{2} × 370 × (220)²

Kinetic energy = 8954000 J

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How much force is needed to accelerate a 2500 kg car at a rate of 3.5 m/s^2?
Sati [7]

F = ma  

F = applied force in newtons = to be determined  

m = mass of the car = 2,500 kg  

a = acceleration of the car = 3.5 m/s²  

F = (2,500 kg)(3.5 m/s²)  

F =8750

4 0
4 years ago
A closely wound search coil has an area of 3.13 cm2, 135 turns, and a resistance of 61.1 Ω. It is connected to a charge-measurin
erastovalidia [21]

Answer:

Explanation:

Let the magnitude of magnetic field be B .

flux passing through the coil's  = area of coil x field x no of turns

Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .

emf induced = dΦ / dt , Φ is magnetic flux.

current i = dΦ /dt x 1/R

charge through the coil = ∫ i dt

= ∫   dΦ /dt x 1/R dt

= 1 / R ∫ dΦ

= Φ / R

Total resistance R = 61.1 + 44.4 = 105.5 ohm .

3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5

B = 3.44 x 10⁻⁵ x 105.5  / 422.55 x 10⁻⁴

= .86 x 10⁻¹

= .086 T .

8 0
3 years ago
What evidence can you cite for the particle nature of light? 1. Refraction phenomenon of light 2. The many colors of light 3. Di
GalinKa [24]
Evidence for the particle nature of light are not: 1. refraction, 2.  many colors of light, 3. diffraction. These are all phenomenon that support wave theory of light. Evidence for particle nature of light is photoelectric effect. Because it was discovered that you need discrete energies of light to eject electrons from a metal surface and not continuous as the wave theory of light suggests. 
3 0
4 years ago
You create a ramp using two text books and a 0.50m board. Using a timer you determine that a cart can roll down the ramp in 0.55
ahrayia [7]

Answer:

The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.

Explanation:

Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:

v=v_0+at\\\\v^2=v_0^2+2ad

Dividing the second equation by the first one, we obtain:

v=\frac{v_0^2+2ad}{v_0+at}

And, since v_0=0, then:

v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s

It means that the velocity at the bottom of the ramp is 1.81m/s.

We could use this data, plus any of the two initial equations, to determine the acceleration:

v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2

So the acceleration is 3.30m/s^2.

7 0
4 years ago
The principle of conservation of momentum is most similar to which of newton's laws of motion?
Effectus [21]
Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
6 0
3 years ago
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