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3 years ago

How is a charged object created?

Physics

1 answer:

Sever21 [200]3 years ago

5 0

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.

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Two wires are identical, except that one is aluminum and one is tungsten. the aluminum wire has a resistance of 0.22 ω. what is

Margaret [11]

The resistance R of a piece of wire is given by
$R=\rho \frac{L}{A}$
where $\rho$ is the resistivity of the material, L is the length of the wire and A is its cross-sectional area.

Using this formula, and labeling with A the aluminum and with T the tungsten wire, we can write the ratio between $R_T$ (the resistance of the tungsten wire) and $R_A$ (the resistance of the aluminum wire):
$\frac{R_T}{R_A}= \frac{\rho_T \frac{L}{A} }{\rho_A \frac{L}{A} }$

the two wires are identical, so L and A are the same for the two wires and simplify in the ratio, and we get:
$R_T = \frac{\rho_T}{\rho_A} R_A$

By using the resistivity of the aluminum: $\rho_A=2.65 \cdot 10^{-8} \Omega m$ and the resistivity of the tungsten: $\rho_T = 5.6 \cdot 10^{-8} \Omega m$ m we can get the resistance of the tungsten wire:
$R_T = \frac{\rho_T}{\rho_A} R_A = \frac{ 5.6 \cdot 10^{-8} \Omega m}{2.65 \cdot 10^{-8} \Omega m} (0.22 \Omega) = 0.46 \Omega$

5 0

3 years ago

A proton with kinetic energy of 1.16×105 eV is fired perpendicular to the face of a large plate that has a uniform charge densit

Nezavi [6.7K]

Answer:

force on the proton = 5.96 × $10^{-14}$ N

Explanation:

given data

kinetic energy = 1.16 × $10^{5}$ eV

charge density of σ = +6.60 μC/m²

solution

we get here force on the proton that is express as

F = qE ....................1

here q is charge on proton i.e = 1.6 × $10^{-19}$ C

and E is electric field due to charge i.e E = $\frac{\sigma }{2*\epsilon_o }$

so put the value in equation 1 we get

force on the proton = 1.6 × $10^{-19}$ × $\frac{6.60*10^{-6}}{2*8.85*10^{-12}}$

force on the proton = 5.96 × $10^{-14}$ N

7 0

3 years ago

I need to know how long the friend will drive before he meets me and how many miles I will have traveled by the time I meet him,

IceJOKER [234]

Let you be at point A while your friend be at point B,
while you are still having lunch,
you friend travels= 27/60*75miles/h=33.75miles
Remaining Distance= 135miles-33.75miles=101.25miles
Take note here is the tricky part, for the remaining distance both you and your friend are driving towards each other,
So first,
Total speed =Adding both ur friend and ur speed= 60+75=135miles/h
Time taken to meet= 101.25miles/135miles/h=0.75h
Total hours ur friend drives= 0.75h+27/60h=1.2h
total distance ur friend drove= 1.2h * 75miles/h= 90km
for the part how far u travelled,
simply take 135miles -90miles=45miles

4 0

3 years ago

An individual motor disconnect must be in sight of the motor controller and must disconnect the controller. NEC definition of in

VashaNatasha [74]

Answer: a) 50

Explanation:

This implies that the controller must be visible at not more than 50ft which is 15m

4 0

3 years ago

Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut e

WARRIOR [948]

Here is the answer of a tutor