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Please select the word from the list that best fits the definition

Elenna [48]

Answer:

Hi... Your answer is impulse

8 0

3 years ago

A long solenoid with 8.22 turns/cm and a radius of 7.00 cm carries a current of 19.4 mA. A current of 3.59 A exists in a straigh

daser333 [38]

Answer:

a. 3.039cm

b.magnetic field is $B=2.958\times10^{-5}T$

Explanation:

Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

$\overrightarrow B = \overrightarrow B_s+ \overrightarrow B_w,\ \ \ \ \ \overrightarrow B_s\perp \overrightarrow B_w$

Angle of net magnetic field from axial direction is given by:

$tan\ \theta=\frac{B_w}{B_s}$ ,

Field due to solenoid:

$B_s=\mu_onI_s, \ \ \ \ n=(8.22 t/cm)(100cm/m)=822turn/m$

Field due to wire:

$B_w=\frac{\mu_oI_w}{2\pi r}$

Therefore, r:

$tan\ \theta=\frac{B_w}{B_s}\\\\=\frac{\mu_oI_w}{2\pi r(\mu_o nI_s)}\\\\r=\frac{I_w}{2\pi nI_stan \ \theta}\\\\r=\frac{3.59A}{2\pi\times822\times19.4\times10^{-3}A \ tan 49.7\textdegree}\\\\r=3.039cm$

Hence, the radial distance is 3.039cm

b.The magnetic field strength is given by:

$B=\sqrt{B_w^2+B_s^2}\\\\tan 49.7\textdegree=\frac{B_w}{B_s}\\\\1.179=\frac{B_w}{B_s}\\\\B_w=1.179B_s\\\\B=\sqrt{(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{3}A)+1.179(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{-3}A)}\\\\B=2.958\times10^{-5}T$

Hence, the magnetic field is $B=2.958\times10^{-5}T$

7 0

4 years ago

We now slowly increase the pressure to 15464.04 Pa while keeping the temperature constant. What is the final volume?

Mila [183]

Answer:

Final volume = 0.42 cubic meters

Explanation:

The question is incomplete. The initial conditions are

Initial temperature , $T_{1}$ = 310 K

Initial volume , $V_{1}$ = 0.5 cubic meter

Number of moles = 2.5

Since, from the ideal gas equation we get,

PV = nRT

P $\times 0.5 = 2.5 \times 8.314 \times 310$

$P_{1}$ = 12886.7 Pa

Final pressure= 15464.04 Pa

Since temperature is constant,

PV = constant

$12886.7 \times 0.5 = 15464.04 \times V$

V = 0.42 cubic meters.

Hence final volume = 0.42 cubic meters

8 0

3 years ago

Advancements in the area of agriculture has started to depend on technology sources for better yield and technology advancements

Ksenya-84 [330]

I don't know if my answer is right or not but on the test I picked ( D)

3 0

4 years ago

El monoxido de carbono reacciona con el hidrogeno gaseoso para producir metanol (ch3oh) calcule el reactivo limite y el reactivo

Orlov [11]

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

$\eta_{CO} = \frac{m}{M}$

En donde:

m: es la masa

M: es el peso molecular

$\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles$

$\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles$

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

$\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles$

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.

$\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles$

$m = 0,071 moles*32,04 g/mol = 2,27 g$

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!

6 0

3 years ago