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k0ka [10]
3 years ago
15

The Port Authority is thinking about dredging the harbor to make it deeper for large ships. Before they do this, they hire a tea

m of environmental scientists and engineers to study the impact of this project. Which statement best explains why this study is important?
Physics
2 answers:
Lisa [10]3 years ago
8 0

Out of the following given choices;

A) It is always difficult to get a project like this approved. This study will help them convince the local community to support the project.

B) If they do not perform the study, and there is a problem during the dredging project, the media could make them look bad.

C)The study will weigh the benefits against the negative impacts so an informed decision can be made.

D)The study will demonstrate the local government's concern for the community's safety.


The answer is; C

Dredging can have a negative impact on the marine environment. Destruction of this ecosystem could have reverberating effects that affect the communities that rely on this ecosystem for livelihoods, such as fishermen. An environmental and feasibility study will help weigh the benefits and demerits of the project and allow for an informed decision to be made.  


Tanya [424]3 years ago
7 0

Answer:

I believe the answer Is C

Explanation:

I got it right on my test

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A flat coil of wire has an area A, N turns, and a resistance R. It is situated in a magnetic field, such that the normal to the
Phantasy [73]

Answer:

3.4 x 10^-4 T

Explanation:

A = 1.5 x 10^-3 m^2

N = 50

R = 180 ohm

q = 9.3 x 106-5 c

Let B be the magnetic field.

Initially the normal of coil is parallel to the magnetic field so the magnetic flux is maximum and then it is rotated by 90 degree, it means the normal of the coil makes an angle 90 degree with the magnetic field so the flux is zero .

Let e be the induced emf and i be the induced current

e = rate of change of magnetic flux

e = dФ / dt

i / R = B x A / t

i x t / ( A x R) = B

B = q / ( A x R)

B = (9.3 x 10^-5) / (1.5 x 10^-3 x 180) = 3.4 x 10^-4 T

6 0
4 years ago
Please Help Physics!
Anton [14]

Answer:

The answer is below!!

Explanation:

The ratio of the wavelength of the waves that travel on the string to the wavelength of the generated sound wave is 0.585

Hope I Helped!!

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6 0
2 years ago
A hollow spherical planet is inhabited by people who live inside it, where the gravitational is zero. When a very massive space
Ulleksa [173]

Answer:

c) nonzero, directed toward the spaceship

Explanation:

As we know that net gravitational force due to spherical shell inside all its points will always be zero

So if planet is a spherical shell then inside the planet net gravitational force is zero on the people living in it

So when massive spaceship land on the surface of planet then the gravitational force of the spaceship is experienced by the people inside the shell

So here the gravitational force on the people is nonzero and it is towards the spaceship which landed on the surface of planet

5 0
3 years ago
Which material(s) listed below is an example of a persistent organic pollutant?
grigory [225]

Answer:

mercury

arsenic

ricin

ddt

Explanation:

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4 0
3 years ago
A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does
Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right) (1)

Where:

y(t) - Position of the mass as a function of time, measured in meters.

A - Amplitude, measured in meters.

k - Spring constant, measured in newtons per meter.

m - Mass of the block, measured in kilograms.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

k = \frac{m\cdot g}{\Delta y} (2)

Where:

g - Gravitational acceleration, measured in meters per square second.

\Delta y - Deformation of the spring due to gravity, measured in meters.

If we know that m=1.65\,kg, g = 9.807\,\frac{m}{s^{2}} and \Delta y = 0.260\,m, then the spring constant is:

k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}

k = 62.237\,\frac{N}{m}

If we know that A = 0.130\,m, k = 62.237\,\frac{N}{m}, m=1.65\,kg, x(t) = 0\,m and \phi = 0\,rad, then (1) is reduced into this form:

0.130\cdot \cos (6.142\cdot t)=0 (1)

And now we solve for t. Given that cosine is a periodic function, we are only interested in the least value of t such that mass reaches equilibrium position. Then:

\cos (6.142\cdot t) = 0

6.142\cdot t = \cos^{-1} 0

t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s

t \approx 0.255\,s

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

4 0
3 years ago
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