Answer:
elliptical orbits
Explanation:
the earth revolves round the sun in an elliptical form
To find velocity on a distance vs time graph, find the slope (of line segment C in this case)
Calculate slope by finding rise (change in x) over run (change in x).
10-30/160-80
-20/80
-1/4
Final answer: B
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
= 
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
<span>Ans : The best way to estimate the population density of pine trees in an actual forest is to count the number of trees in a small area and than multiply to find the number in a large area. To get the most accurate estimate, your sample area should be typical of the larger area.
Suppose you count 10 pine tree in 100 sq meters of the forest. If the entire forest were 100 times the size, you would multiply your count by 100 to estimate the total population density, or 1000 (10X100) pine trees.</span>
Answer:
No ejection of photo electron takes place.
Explanation:
When a photon of suitable energy falls on cathode, then the photoelectrons is emitted from the cathode. This phenomenon is called photo electric effect.
The minimum energy required to just eject an electron is called work function.
The photo electric equation is
E = W + KE
where, E is the incident energy, W is the work function and KE is the kinetic energy.
W = h f
where. h is the Plank's constant and f is the threshold frequency.
Now, when the violet light is falling, no electrons is ejected. When the red light is falling, whose frequency is less than the violet light, then again no photo electron is ejected from the metal surface.
