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BigorU [14]
3 years ago
7

Malik stops at the grocery store to buy a bag of diapers and 2 cans of formula. He spends a total of $37. The next week he stops

and buys 2 bags of diapers and 5 cans of formula for a total of $87. How much does a bag of diapers cost? How much is one can of formula?
Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

Diapers costs $11 and formula is $13.

Step-by-step explanation:

Let's name diapers as A and formula as B.

Simply the equations:

1A + 2B = $37(1)

2A + 5B = $87(2)

Clear D from one equation.

A = $37 - 2B(1)

Replace D into the other equation.

2*($37 - 2B) + 5B = $87(2)

$74 - 4B + 5B = $87

$74 + B = $87

B = $87 - $74 = $13

Find A, now knowing B.

A = $37 - 2($13)

A = $37 - $26 = $11

Vaselesa [24]3 years ago
7 0

Answer:

Cost of a bag of diapers is $11 and cost of one can of formula is $13.

Step-by-step explanation:

Let cost of each diaper = $D and cost of each cans of formula = $C

Malik shops a bag of diapers and 2 cans of formula.

He spends total of $37.

So the equation will be

D + 2C = 37 -------(1)

Next week he stops and buys 2 bags of diapers and 5 cans of formula.

He spends total $87.

Equation for this purchase will be

2D + 5C = 87 ----------(2)

Multiply equation (1) by 2 and subtract it from equation (2).

2(D + 2C) - (2D + 5C) = 2×37 - 87

2D + 4C - 2D - 5C = 74 - 87

-C = - 13

C = 13

From equation (1)

D + 2×13 = 37

D + 26 = 37

D = 37 - 26

D = 11

Therefore, cost of a bag of diapers is $11 and cost of one can of formula is $13.

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B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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