Question

There are 6 marbles in a bag: 1 blue, 1 red, 1 white, 1 yellow, 1 green, and 1 black. Mary picks one marble at random and then her sister chooses another from those left in the bag.
What is the probability that Mary picks the red marble and her sister picks the blue marble?

Answer 1

Answer:

1 in 30

Step-by-step explanation:

1 in 6 chance Mary picks the red marble in the first place. After this there is a 1 in 5 chance her sister picks the blue one. 5 multiplied by 6 is 30.

Answer 2

The probability that Mary picks the red marble and her sister picks the blue marble is $\frac{1}{30}$ .

Concept:

• Firstly, we need to find the probability of Mary picking a red marble from the 6 marbles.
• Secondly. we need to find the probability of Mary's sister picking a blue marble from the 5 left marbles.
• As both are mutually exclusive events , the required probability is the multiplication of both above.

How to solve the given question?

• P(A) = Mary picking a red marble out of 6 marbles = $\frac{1}{6}$
• P(B) = Mary's sister picking a blue marble out 5 left marbles = $\frac{1}{5}$
• P(E) = Required probability = P(A) × P(B) = $\frac{1}{6}$ × $\frac{1}{5}$ =

Thus, the probability that Mary picks the red marble and her sister picks the blue marble is $\frac{1}{30}$ .

Learn more about probability here:

brainly.com/question/24756209

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