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Romashka [77]
2 years ago
8

Please help!!!! Find the value of x.

Mathematics
1 answer:
Blababa [14]2 years ago
4 0

Answer: 84

Step-by-step explanation:

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Jamal has a pair of shoes that have a total mass of 960 grams and four identical books that have a total mass of 2 kilograms. Wh
Andreyy89

Answer: One book has a greater mass.

Step-by-step explanation:

Jamal has a pair of shoes with a total mass of 960 grams. This means that each shoe has a mass of:

960 grams ÷ 2= 480 grams per shoe.

Jamal also has four identical books with a total mass of 2 kilograms. Note that 1000 grams make a kilograms. Therefore 2 kilograms will be (2 × 1000 grams) = 2000 grams.

Each book will have a mass of:

2000 ÷ 4 = 500 grams per book.

One shoe has a mass of 960 divided 2 = 480 grams . One book has a mass of 2000 divided 4 = 500 grams . So one book has a greater mass.

8 0
3 years ago
PLEASE HELP!!
Mamont248 [21]

2 and 8 are alternate exterior angles

5 0
3 years ago
Read 2 more answers
Paul borrowed $360 to be repaid in one year. He paid 10% interest and a service
Art [367]

Answer:

Step-by-step explanation:

Hey, do you mean what is the final charge? If so, then look at my next steps

If you mean the final charge then first multiply 10% by 360 , basically 10/100 multiplied by $360 which is equals to $36. Since it is interest, add $36 to $360. The answer will be $396. Then you add on the $19 which would bring the total to $415.

Hehe I am no expert but this is what I did . Tried my best

4 0
3 years ago
Find the indicated IQ score. The graph to the right depicts IQ scores of​ adults, and those scores are normally distributed with
larisa86 [58]

Based on the mean, standard deviation, and the graph, the indicated IQ score would be 115.

<h3>What is the indicated IQ score?</h3>

First, find the z value:

P(Z<z) = 1 - tail value

= 1 - 0.1587

= 0.8413

According to the z-value, this gives a value of:

z = 1

The indicated IQ score is:

= mean + z value z standard deviation

= 100 + 1 x 15

= 115

Find out more on normal distributions at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0
andreev551 [17]

Recall the angle sum identity for cosine:

cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) + sin(<em>x</em>) sin(<em>y</em>)

==>   sin(<em>x</em>) sin(<em>y</em>) = 1/2 (cos(<em>x</em> - <em>y</em>) - cos(<em>x</em> + <em>y</em>))

Then rewrite the equation as

sin(4<em>x</em>) sin(5<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>) - sin(2<em>x</em>) sin(<em>x</em>) = 0

1/2 (cos(-<em>x</em>) - cos(9<em>x</em>)) + 1/2 (cos(<em>x</em>) - cos(7<em>x</em>)) - 1/2 (cos(<em>x</em>) - cos(3<em>x</em>)) = 0

1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

sin(5<em>x</em>) sin(-4<em>x</em>) + sin(5<em>x</em>) sin(-2<em>x</em>) = 0

-sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Rewrite the equation again as

sin(5<em>x</em>) (2 sin(2<em>x</em>) cos(2<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) sin(2<em>x</em>) (2 cos(2<em>x</em>) + 1) = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   2 cos(2<em>x</em>) + 1 = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   cos(2<em>x</em>) = -1/2

sin(5<em>x</em>) = 0   ==>   5<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   5<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   5<em>x</em> = 2<em>nπ</em>   <u>or</u>   5<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = 2<em>nπ</em>/5   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/5

sin(2<em>x</em>) = 0   ==>   2<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   2<em>x</em> = 2<em>nπ</em>   <u>or</u>   2<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = <em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/2

cos(2<em>x</em>) = -1/2   ==>   2<em>x</em> = arccos(-1/2) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -arccos(-1/2) + 2<em>nπ</em>

… … … … … …    ==>   2<em>x</em> = 2<em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -2<em>π</em>/3 + 2<em>nπ</em>

… … … … … …    ==>   <em>x</em> = <em>π</em>/3 + <em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

<em />

(where <em>n</em> is any integer)

5 0
3 years ago
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