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PolarNik [594]
1 year ago
11

Calculate the accumulated amount after 3 years, if R5 000 is invested at an interest rate of 10% compounded quarterly?​

Mathematics
2 answers:
VARVARA [1.3K]1 year ago
7 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &3 \end{cases} \\\\\\ A=5000\left(1+\frac{0.10}{4}\right)^{4\cdot 3}\implies A=5000(1.025)^{12}\implies A\approx 6724.44

timofeeve [1]1 year ago
3 0

Answer:

R6,724.44 or so I think that's right

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Complete the table of values fory=2x^2+x
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Complete question:

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<u>Complete table of values</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

Step-by-step explanation:

Given;

y = 2x² + 2x - 3

To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.

when, x = -2

y = 2(-2)² + 2(-2) - 3

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when x = -1

y = 2(-1)² + 2(-1) - 3

y = 2 - 2 - 3

y = -3

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y = 2(0)² + 2(0) - 3

y = 0 - 0 - 3

y = -3

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y = 2(1)² + 2(1) - 3

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when x = 2

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x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

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