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PolarNik [594]
2 years ago
11

Calculate the accumulated amount after 3 years, if R5 000 is invested at an interest rate of 10% compounded quarterly?​

Mathematics
2 answers:
VARVARA [1.3K]2 years ago
7 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &3 \end{cases} \\\\\\ A=5000\left(1+\frac{0.10}{4}\right)^{4\cdot 3}\implies A=5000(1.025)^{12}\implies A\approx 6724.44

timofeeve [1]2 years ago
3 0

Answer:

R6,724.44 or so I think that's right

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Read 2 more answers
Write an algebraic equation based on the description. Two angles form a linear pair. The measure of one angle is 24° more than t
IgorC [24]
<h2><u>Answer:-</u></h2>

Given:

Two angles form a linear pair.

It means sum of their measures = 180°.

And,

Measure of one angle is 24° greater than the other.

Let the other angle be x.

→ First angle = (x + 24)

According to the question,

<h3>→ x + x + 24 = 180</h3>

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→ 2x = 156

→ x = 156/2

<h3>→ X = 78°</h3>

<u>There</u><u>fore</u><u>,</u>

  • 1st angle = 78°
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4 0
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