Answer:
s can take any real value.
Step-by-step explanation:
Given that
-2(6+s)_>-15-2s
Distribute -2 over 6+s
-12-2s >= -15-2s
Simplify both the sides
Add 2s to both the sides.
We get 2s cancel out and -12>=-15 which is true.
Hence the given inequality is valid for all values of s.
This is a special case of inequality which has infinite number of solutions.
s can take any real number and this inequality is valid.
Solution of inequality: -12 ≥ -15 Which is true.
Given data:
Equation:-2(6+s)_>-15-2s
=-12 - 2s ≥ - 15 -2s
By dividing -2s on both sides:
= -12 - 2s/-2s ≥ - 15 -2s/-2s
= -12 ≥ -15
-2(6+s)_>-15-2s = -12 ≥ -15
M^4
Here use product law which state- same base power should add
M^7-3
i am 90% sure this is correct
