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2 years ago

12

Help I just not that smart

2 answers:

Lubov Fominskaja [6]2 years ago

4 0

Answer:

$1\frac{1}{9}$ gallons of paint

Step-by-step explanation:

paint =

2/3 ---- 3/5

x ---- 1

$x = \frac{\frac{2}{3} }{\frac{3}{5} } =\frac{(2)(5)}{(3)(3)} =\frac{10}{9}$

$x=1\frac{1}{9}$

Hope this helps

Gelneren [198K]2 years ago

4 0

Answer: 1 and 1 over 9 as a fraction .

Step-by-step explanation: HOPE IT HELPS YOU .

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Which cylinders with base area B and height h have volumes

faust18 [17]

Answer:

1) $B=15in^{2},h=17in$

3) $B=7.2in^{2},h=6.5in$

4) $B=8.5in^{2},h=30in$

Step-by-step explanation:

1. You can calculate the volume of a cylinder with the following formula:

$V=B*h$

Where $B$ is the area of the base and $h$ is the height.

2. Therefore, you only need to multiply the area of the base by the height in each option:

1) $V_1=15in^{2}*17in=255in^{3}$

2) $V_2=7.2in^{2}*6.5in=46.8in^{3}$

3) $V_3=34in^{2}*7.5in=255in^{3}$

4) $V_4=8.5in^{2}*30in=255in^{3}$

3. Therefore, the options 1), 3) and 4) have equal volumes.

6 0

4 years ago

Which statements are true about the solution of 15 > 22+ x? Select three options.

Evgesh-ka [11]

Answer:

$x \leqslant - 7 \\ the \: graph \: has \: a \: closed \: circle \\ - 7 \: is \: a \: part \: of \: the \: solution$

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3 years ago

How to make a dot plot

eimsori [14]

Answer:

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4 years ago

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3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

4 0

3 years ago